11002140434232 has 96 divisors (see below), whose sum is σ = 30137712508800. Its totient is φ = 3625644151872.

The previous prime is 11002140434209. The next prime is 11002140434287. The reversal of 11002140434232 is 23243404120011.

11002140434232 is a `hidden beast` number, since 1 + 1 + 0 + 0 + 21 + 404 + 3 + 4 + 232 = 666.

It is a super-3 number, since 3×11002140434232³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11002140434196 and 11002140434205.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2285619 + ... + 5218077.

It is an arithmetic number, because the mean of its divisors is an integer number (313934505300).

Almost surely, 2^{11002140434232} is an apocalyptic number.

11002140434232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11002140434232, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15068856254400).

11002140434232 is an abundant number, since it is smaller than the sum of its proper divisors (19135572074568).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11002140434232 is a wasteful number, since it uses less digits than its factorization.

11002140434232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2933065 (or 2933058 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 11002140434232 its reverse (23243404120011), we get a palindrome (34245544554243).

The spelling of 11002140434232 in words is "eleven trillion, two billion, one hundred forty million, four hundred thirty-four thousand, two hundred thirty-two".