110111212200103 has 2 divisors, whose sum is σ = 110111212200104. Its totient is φ = 110111212200102.

The previous prime is 110111212200097. The next prime is 110111212200109. The reversal of 110111212200103 is 301002212111011.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (110111212200097) and next prime (110111212200109).

It is a cyclic number.

It is not a de Polignac number, because 110111212200103 - 2³³ = 110102622265511 is a prime.

It is a super-3 number, since 3×110111212200103³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110111212200109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55055606100051 + 55055606100052.

It is an arithmetic number, because the mean of its divisors is an integer number (55055606100052).

Almost surely, 2^{110111212200103} is an apocalyptic number.

110111212200103 is a deficient number, since it is larger than the sum of its proper divisors (1).

110111212200103 is an equidigital number, since it uses as much as digits as its factorization.

110111212200103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 110111212200103 its reverse (301002212111011), we get a palindrome (411113424311114).

The spelling of 110111212200103 in words is "one hundred ten trillion, one hundred eleven billion, two hundred twelve million, two hundred thousand, one hundred three".