110111213200421 has 2 divisors, whose sum is σ = 110111213200422. Its totient is φ = 110111213200420.

The previous prime is 110111213200411. The next prime is 110111213200423. The reversal of 110111213200421 is 124002312111011.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110102524350625 + 8688849796 = 10492975^2 + 93214^2 .

It is an emirp because it is prime and its reverse (124002312111011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110111213200421 - 2¹⁸ = 110111212938277 is a prime.

Together with 110111213200423, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 110111213200393 and 110111213200402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110111213200423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55055606600210 + 55055606600211.

It is an arithmetic number, because the mean of its divisors is an integer number (55055606600211).

Almost surely, 2^{110111213200421} is an apocalyptic number.

It is an amenable number.

110111213200421 is a deficient number, since it is larger than the sum of its proper divisors (1).

110111213200421 is an equidigital number, since it uses as much as digits as its factorization.

110111213200421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 20.

Adding to 110111213200421 its reverse (124002312111011), we get a palindrome (234113525311432).

The spelling of 110111213200421 in words is "one hundred ten trillion, one hundred eleven billion, two hundred thirteen million, two hundred thousand, four hundred twenty-one".