Base | Representation |
---|---|
bin | 100000110100011… |
… | …0100100100001110 |
3 | 2211202010210000000 |
4 | 1001220310210032 |
5 | 4223403020420 |
6 | 301134545130 |
7 | 36201134154 |
oct | 10150644416 |
9 | 2752123000 |
10 | 1101220110 |
11 | 515678a71 |
12 | 2689681a6 |
13 | 1471ba143 |
14 | a63793d4 |
15 | 66a27690 |
hex | 41a3490e |
1101220110 has 128 divisors (see below), whose sum is σ = 3044574720. Its totient is φ = 286584480.
The previous prime is 1101220097. The next prime is 1101220117. The reversal of 1101220110 is 110221011.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (9).
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1101220092 and 1101220101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1101220117) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 939825 + ... + 940995.
It is an arithmetic number, because the mean of its divisors is an integer number (23785740).
Almost surely, 21101220110 is an apocalyptic number.
1101220110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 1101220110, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1522287360).
1101220110 is an abundant number, since it is smaller than the sum of its proper divisors (1943354610).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1101220110 is an equidigital number, since it uses as much as digits as its factorization.
1101220110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1242 (or 1224 counting only the distinct ones).
The product of its (nonzero) digits is 4, while the sum is 9.
The square root of 1101220110 is about 33184.6366561395. The cubic root of 1101220110 is about 1032.6616396700.
Adding to 1101220110 its reverse (110221011), we get a palindrome (1211441121).
Subtracting from 1101220110 its reverse (110221011), we obtain a palindrome (990999099).
The spelling of 1101220110 in words is "one billion, one hundred one million, two hundred twenty thousand, one hundred ten".
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