11031434130 has 64 divisors (see below), whose sum is σ = 28205013888. Its totient is φ = 2751667200.

The previous prime is 11031434093. The next prime is 11031434131. The reversal of 11031434130 is 3143413011.

It is a junction number, because it is equal to n+sod(n) for n = 11031434097 and 11031434106.

It is not an unprimeable number, because it can be changed into a prime (11031434131) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16780 + ... + 149480.

It is an arithmetic number, because the mean of its divisors is an integer number (440703342).

Almost surely, 2^11031434130 is an apocalyptic number.

11031434130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 11031434130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14102506944).

11031434130 is an abundant number, since it is smaller than the sum of its proper divisors (17173579758).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11031434130 is a wasteful number, since it uses less digits than its factorization.

11031434130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 132891.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 11031434130 its reverse (3143413011), we get a palindrome (14174847141).

The spelling of 11031434130 in words is "eleven billion, thirty-one million, four hundred thirty-four thousand, one hundred thirty".