Base | Representation |
---|---|
bin | 1010000010001010001100… |
… | …1000110000111101000000 |
3 | 1110001200001220002121222111 |
4 | 2200202203020300331000 |
5 | 2421222433012000000 |
6 | 35244043443545104 |
7 | 2216023344154243 |
oct | 240424310607500 |
9 | 43050056077874 |
10 | 11032213000000 |
11 | 357380a6a1665 |
12 | 12a214998b194 |
13 | 62044411c9ba |
14 | 2a1d6788325a |
15 | 141e8e71bcba |
hex | a08a3230f40 |
11032213000000 has 98 divisors (see below), whose sum is σ = 27364711797518. Its totient is φ = 4412884800000.
The previous prime is 11032212999991. The next prime is 11032213000001. The reversal of 11032213000000 is 31223011.
It can be written as a sum of positive squares in 7 ways, for example, as 11016132731136 + 16080268864 = 3319056^2 + 126808^2 .
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11032213000001) by changing a digit.
It is a polite number, since it can be written in 13 ways as a sum of consecutive naturals, for example, 4516107 + ... + 6516106.
Almost surely, 211032213000000 is an apocalyptic number.
11032213000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11032213000000 is an abundant number, since it is smaller than the sum of its proper divisors (16332498797518).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11032213000000 is an frugal number, since it uses more digits than its factorization.
11032213000000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11032255 (or 11032220 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 11032213000000 its reverse (31223011), we get a palindrome (11032244223011).
The spelling of 11032213000000 in words is "eleven trillion, thirty-two billion, two hundred thirteen million", and thus it is an aban number.
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