Base | Representation |
---|---|
bin | 11001001111100011100111… |
… | …100101110010111111101110 |
3 | 112120002102112122001020001111 |
4 | 121033203213211302333232 |
5 | 104022423332212041420 |
6 | 1032041550440502234 |
7 | 32245642024424662 |
oct | 3117434745627756 |
9 | 476072478036044 |
10 | 111020200112110 |
11 | 32413447744313 |
12 | 1055056047a97a |
13 | 49c421053ac53 |
14 | 1d5b5990808a2 |
15 | cc7d5457245a |
hex | 64f8e7972fee |
111020200112110 has 96 divisors (see below), whose sum is σ = 210415445991936. Its totient is φ = 42164883417600.
The previous prime is 111020200112033. The next prime is 111020200112137. The reversal of 111020200112110 is 11211002020111.
It is a happy number.
It is a super-3 number, since 3×1110202001121103 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 133577952 + ... + 134406508.
It is an arithmetic number, because the mean of its divisors is an integer number (2191827562416).
Almost surely, 2111020200112110 is an apocalyptic number.
111020200112110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
111020200112110 is a deficient number, since it is larger than the sum of its proper divisors (99395245879826).
111020200112110 is a wasteful number, since it uses less digits than its factorization.
111020200112110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 828890 (or 828859 counting only the distinct ones).
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 111020200112110 its reverse (11211002020111), we get a palindrome (122231202132221).
The spelling of 111020200112110 in words is "one hundred eleven trillion, twenty billion, two hundred million, one hundred twelve thousand, one hundred ten".
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