Base | Representation |
---|---|
bin | 10000001010110100100… |
… | …101100100110000010000 |
3 | 10221020000122120221221222 |
4 | 100022310211210300100 |
5 | 121201044103423440 |
6 | 2210240252104212 |
7 | 143163604211435 |
oct | 20126445446020 |
9 | 3836018527858 |
10 | 1111131311120 |
11 | 399256726876 |
12 | 15b417765068 |
13 | 80a18c8a0bc |
14 | 3bac9999b8c |
15 | 1dd82d2c2b5 |
hex | 102b4964c10 |
1111131311120 has 80 divisors (see below), whose sum is σ = 2823580850688. Its totient is φ = 404814428160.
The previous prime is 1111131311117. The next prime is 1111131311123. The reversal of 1111131311120 is 211131311111.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (1111131311117) and next prime (1111131311123).
It is a tau number, because it is divible by the number of its divisors (80).
It is a super-2 number, since 2×11111313111202 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (17).
It is not an unprimeable number, because it can be changed into a prime (1111131311123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13135394 + ... + 13219713.
Almost surely, 21111131311120 is an apocalyptic number.
1111131311120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1111131311120 is an abundant number, since it is smaller than the sum of its proper divisors (1712449539568).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1111131311120 is a wasteful number, since it uses less digits than its factorization.
1111131311120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26355168 (or 26355162 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 17.
Adding to 1111131311120 its reverse (211131311111), we get a palindrome (1322262622231).
Subtracting from 1111131311120 its reverse (211131311111), we obtain a palindrome (900000000009).
The spelling of 1111131311120 in words is "one trillion, one hundred eleven billion, one hundred thirty-one million, three hundred eleven thousand, one hundred twenty".
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