Base | Representation |
---|---|
bin | 10000001011000110100… |
… | …101000000110000001110 |
3 | 10221020210200120010221020 |
4 | 100023012211000300032 |
5 | 121202203341403200 |
6 | 2210330233415010 |
7 | 143204230633506 |
oct | 20130645006016 |
9 | 3836720503836 |
10 | 1111433153550 |
11 | 3993a1049525 |
12 | 15b4a086a466 |
13 | 80a666816a5 |
14 | 3bb17acca06 |
15 | 1dd9e5a1ea0 |
hex | 102c6940c0e |
1111433153550 has 24 divisors (see below), whose sum is σ = 2756354221176. Its totient is φ = 296382174240.
The previous prime is 1111433153521. The next prime is 1111433153561. The reversal of 1111433153550 is 553513341111.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3704777029 + ... + 3704777328.
It is an arithmetic number, because the mean of its divisors is an integer number (114848092549).
Almost surely, 21111433153550 is an apocalyptic number.
1111433153550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1111433153550 is an abundant number, since it is smaller than the sum of its proper divisors (1644921067626).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1111433153550 is a wasteful number, since it uses less digits than its factorization.
1111433153550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7409554372 (or 7409554367 counting only the distinct ones).
The product of its (nonzero) digits is 13500, while the sum is 33.
Adding to 1111433153550 its reverse (553513341111), we get a palindrome (1664946494661).
The spelling of 1111433153550 in words is "one trillion, one hundred eleven billion, four hundred thirty-three million, one hundred fifty-three thousand, five hundred fifty".
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