Base | Representation |
---|---|
bin | 10100101101110111… |
… | …00100110100011100 |
3 | 1001201010020222000000 |
4 | 22112323210310130 |
5 | 140234231244200 |
6 | 5035345534300 |
7 | 542421403344 |
oct | 122673446434 |
9 | 31633228000 |
10 | 11122134300 |
11 | 4798178132 |
12 | 21a4944390 |
13 | 108331ab74 |
14 | 7771c3d24 |
15 | 451667300 |
hex | 296ee4d1c |
11122134300 has 126 divisors (see below), whose sum is σ = 36186230808. Its totient is φ = 2965883040.
The previous prime is 11122134299. The next prime is 11122134301. The reversal of 11122134300 is 343122111.
11122134300 is a `hidden beast` number, since 1 + 11 + 221 + 3 + 430 + 0 = 666.
It is an interprime number because it is at equal distance from previous prime (11122134299) and next prime (11122134301).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11122134301) by changing a digit.
It is a polite number, since it can be written in 41 ways as a sum of consecutive naturals, for example, 3384 + ... + 149183.
It is an arithmetic number, because the mean of its divisors is an integer number (287192308).
Almost surely, 211122134300 is an apocalyptic number.
11122134300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11122134300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18093115404).
11122134300 is an abundant number, since it is smaller than the sum of its proper divisors (25064096508).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11122134300 is a wasteful number, since it uses less digits than its factorization.
11122134300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 152599 (or 152577 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 11122134300 its reverse (343122111), we get a palindrome (11465256411).
The spelling of 11122134300 in words is "eleven billion, one hundred twenty-two million, one hundred thirty-four thousand, three hundred".
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