Base | Representation |
---|---|
bin | 10000001100111101010… |
… | …001100110100111010010 |
3 | 10221102221110201210102010 |
4 | 100030331101212213102 |
5 | 121220243141220300 |
6 | 2211300012203350 |
7 | 143304461362155 |
oct | 20147521464722 |
9 | 3842843653363 |
10 | 1113424554450 |
11 | 39a22315249a |
12 | 15b957769556 |
13 | 80cc3107a10 |
14 | 3bc66389c9c |
15 | 1de69316a50 |
hex | 1033d4669d2 |
1113424554450 has 144 divisors (see below), whose sum is σ = 3048007290048. Its totient is φ = 267388224000.
The previous prime is 1113424554449. The next prime is 1113424554469. The reversal of 1113424554450 is 544554243111.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a junction number, because it is equal to n+sod(n) for n = 1113424554399 and 1113424554408.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 3108115 + ... + 3447785.
It is an arithmetic number, because the mean of its divisors is an integer number (21166717292).
Almost surely, 21113424554450 is an apocalyptic number.
1113424554450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 1113424554450, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1524003645024).
1113424554450 is an abundant number, since it is smaller than the sum of its proper divisors (1934582735598).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1113424554450 is a wasteful number, since it uses less digits than its factorization.
1113424554450 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 339781 (or 339735 counting only the distinct ones).
The product of its (nonzero) digits is 192000, while the sum is 39.
Adding to 1113424554450 its reverse (544554243111), we get a palindrome (1657978797561).
The spelling of 1113424554450 in words is "one trillion, one hundred thirteen billion, four hundred twenty-four million, five hundred fifty-four thousand, four hundred fifty".
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