Base | Representation |
---|---|
bin | 10000010100001101011… |
… | …100110100000000011000 |
3 | 10222012001012102011120000 |
4 | 100110031130310000120 |
5 | 121332220300333422 |
6 | 2215024442533000 |
7 | 144001452532146 |
oct | 20241534640030 |
9 | 3865035364500 |
10 | 1121212121112 |
11 | 3a255a0155a6 |
12 | 16136b807160 |
13 | 8196462c525 |
14 | 3c3a4756596 |
15 | 1e272d4dcac |
hex | 1050d734018 |
1121212121112 has 80 divisors (see below), whose sum is σ = 3143230605240. Its totient is φ = 373404328704.
The previous prime is 1121212121041. The next prime is 1121212121143. The reversal of 1121212121112 is 2111212121211.
It is a happy number.
It is a super-2 number, since 2×11212121211122 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a nude number because it is divisible by every one of its digits.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 42673 + ... + 1498080.
Almost surely, 21121212121112 is an apocalyptic number.
1121212121112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1121212121112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1571615302620).
1121212121112 is an abundant number, since it is smaller than the sum of its proper divisors (2022018484128).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1121212121112 is a wasteful number, since it uses less digits than its factorization.
1121212121112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1541894 (or 1541881 counting only the distinct ones).
The product of its digits is 32, while the sum is 18.
Adding to 1121212121112 its reverse (2111212121211), we get a palindrome (3232424242323).
Subtracting 1121212121112 from its reverse (2111212121211), we obtain a palindrome (990000000099).
The spelling of 1121212121112 in words is "one trillion, one hundred twenty-one billion, two hundred twelve million, one hundred twenty-one thousand, one hundred twelve".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •