Base | Representation |
---|---|
bin | 1010001100101000011100… |
… | …1110001111110000110100 |
3 | 1110200212110211212221011110 |
4 | 2203022013032033300310 |
5 | 2432144422111120200 |
6 | 35502441040235020 |
7 | 2235023054404521 |
oct | 243120716176064 |
9 | 43625424787143 |
10 | 11212133301300 |
11 | 3633047a48a48 |
12 | 1310ba090ba70 |
13 | 6343b83ab049 |
14 | 2aa954c54148 |
15 | 1469bee30b50 |
hex | a328738fc34 |
11212133301300 has 72 divisors (see below), whose sum is σ = 32440913641696. Its totient is φ = 2989858469760.
The previous prime is 11212133301277. The next prime is 11212133301319. The reversal of 11212133301300 is 310333121211.
It is a happy number.
It is a super-2 number, since 2×112121333013002 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 23789739 + ... + 24256461.
Almost surely, 211212133301300 is an apocalyptic number.
11212133301300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11212133301300 is an abundant number, since it is smaller than the sum of its proper divisors (21228780340396).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11212133301300 is a wasteful number, since it uses less digits than its factorization.
11212133301300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 546817 (or 546810 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 11212133301300 its reverse (310333121211), we get a palindrome (11522466422511).
The spelling of 11212133301300 in words is "eleven trillion, two hundred twelve billion, one hundred thirty-three million, three hundred one thousand, three hundred".
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