Base | Representation |
---|---|
bin | 11001011111110110100111… |
… | …100111010110010011010100 |
3 | 112201001111020022011202200120 |
4 | 121133312213213112103110 |
5 | 104144300422442210200 |
6 | 1034300242401511540 |
7 | 32422566355105524 |
oct | 3137664747262324 |
9 | 481044208152616 |
10 | 112140113241300 |
11 | 3280539a48aa71 |
12 | 106b16090425b0 |
13 | 4a759c89c62b1 |
14 | 1d99879099684 |
15 | ce704d32e9a0 |
hex | 65fda79d64d4 |
112140113241300 has 72 divisors (see below), whose sum is σ = 324459882717600. Its totient is φ = 29903923739520.
The previous prime is 112140113241287. The next prime is 112140113241301. The reversal of 112140113241300 is 3142311041211.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112140113241301) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 120393766 + ... + 121321634.
Almost surely, 2112140113241300 is an apocalyptic number.
112140113241300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
112140113241300 is an abundant number, since it is smaller than the sum of its proper divisors (212319769476300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112140113241300 is a wasteful number, since it uses less digits than its factorization.
112140113241300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1330745 (or 1330738 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 112140113241300 its reverse (3142311041211), we get a palindrome (115282424282511).
The spelling of 112140113241300 in words is "one hundred twelve trillion, one hundred forty billion, one hundred thirteen million, two hundred forty-one thousand, three hundred".
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