112314120 has 64 divisors (see below), whose sum is σ = 338869440. Its totient is φ = 29779200.

The previous prime is 112314113. The next prime is 112314127. The reversal of 112314120 is 21413211.

It is an interprime number because it is at equal distance from previous prime (112314113) and next prime (112314127).

It is a super-2 number, since 2×112314120² = 25228923102748800, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 112314120.

It is not an unprimeable number, because it can be changed into a prime (112314127) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19135 + ... + 24305.

It is an arithmetic number, because the mean of its divisors is an integer number (5294835).

Almost surely, 2^112314120 is an apocalyptic number.

112314120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 112314120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (169434720).

112314120 is an abundant number, since it is smaller than the sum of its proper divisors (226555320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112314120 is a wasteful number, since it uses less digits than its factorization.

112314120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5366 (or 5362 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 112314120 is about 10597.8356280894. The cubic root of 112314120 is about 482.4786714153.

Adding to 112314120 its reverse (21413211), we get a palindrome (133727331).

Subtracting from 112314120 its reverse (21413211), we obtain a palindrome (90900909).

It can be divided in two parts, 11231 and 4120, that added together give a palindrome (15351).

The spelling of 112314120 in words is "one hundred twelve million, three hundred fourteen thousand, one hundred twenty".