112423121123130 has 96 divisors (see below), whose sum is σ = 300415405777344. Its totient is φ = 29153304165888.

The previous prime is 112423121123123. The next prime is 112423121123143. The reversal of 112423121123130 is 31321121324211.

112423121123130 is a `hidden beast` number, since 1 + 1 + 2 + 4 + 231 + 2 + 112 + 313 + 0 = 666.

112423121123130 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-3 number, since 3×112423121123130³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 112423121123094 and 112423121123103.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 63108079 + ... + 64865058.

It is an arithmetic number, because the mean of its divisors is an integer number (3129327143514).

Almost surely, 2^{112423121123130} is an apocalyptic number.

112423121123130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

112423121123130 is an abundant number, since it is smaller than the sum of its proper divisors (187992284654214).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112423121123130 is a wasteful number, since it uses less digits than its factorization.

112423121123130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 127973420 (or 127973417 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 112423121123130 its reverse (31321121324211), we get a palindrome (143744242447341).

The spelling of 112423121123130 in words is "one hundred twelve trillion, four hundred twenty-three billion, one hundred twenty-one million, one hundred twenty-three thousand, one hundred thirty".