Base | Representation |
---|---|
bin | 11001101100110011100000… |
… | …110000010100001000100100 |
3 | 112211012120112002221220112210 |
4 | 121230303200300110020210 |
5 | 104303341201302421200 |
6 | 1040221154104243420 |
7 | 32544104664556005 |
oct | 3154634060241044 |
9 | 484176462856483 |
10 | 113030130123300 |
11 | 33018899846515 |
12 | 10815bb5a70570 |
13 | 4b0b907126090 |
14 | 1dca98a6751ac |
15 | d1028e1d5650 |
hex | 66cce0c14224 |
113030130123300 has 144 divisors (see below), whose sum is σ = 352426205154240. Its totient is φ = 27804164328960.
The previous prime is 113030130123289. The next prime is 113030130123343. The reversal of 113030130123300 is 3321031030311.
It is a super-3 number, since 3×1130301301233003 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3883290 + ... + 15528689.
It is an arithmetic number, because the mean of its divisors is an integer number (2447404202460).
Almost surely, 2113030130123300 is an apocalyptic number.
113030130123300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113030130123300 is an abundant number, since it is smaller than the sum of its proper divisors (239396075030940).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113030130123300 is a wasteful number, since it uses less digits than its factorization.
113030130123300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19413502 (or 19413495 counting only the distinct ones).
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 113030130123300 its reverse (3321031030311), we get a palindrome (116351161153611).
The spelling of 113030130123300 in words is "one hundred thirteen trillion, thirty billion, one hundred thirty million, one hundred twenty-three thousand, three hundred".
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