Base | Representation |
---|---|
bin | 11001101101111001001111… |
… | …111101001110011111000000 |
3 | 112211110201210122002002202012 |
4 | 121231321033331032133000 |
5 | 104311103030104114130 |
6 | 1040315420244512052 |
7 | 32552365410115463 |
oct | 3155711775163700 |
9 | 484421718062665 |
10 | 113105010223040 |
11 | 330476246a1770 |
12 | 108286130ab628 |
13 | 4b159ab60b8c4 |
14 | 1dd045145b2da |
15 | d121c2e66995 |
hex | 66de4ff4e7c0 |
113105010223040 has 112 divisors (see below), whose sum is σ = 293820337306080. Its totient is φ = 41128483246080.
The previous prime is 113105010223031. The next prime is 113105010223123. The reversal of 113105010223040 is 40322010501311.
It is a junction number, because it is equal to n+sod(n) for n = 113105010222997 and 113105010223015.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 284967446 + ... + 285364074.
Almost surely, 2113105010223040 is an apocalyptic number.
113105010223040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113105010223040 is an abundant number, since it is smaller than the sum of its proper divisors (180715327083040).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113105010223040 is a wasteful number, since it uses less digits than its factorization.
113105010223040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 477670 (or 477660 counting only the distinct ones).
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 113105010223040 its reverse (40322010501311), we get a palindrome (153427020724351).
The spelling of 113105010223040 in words is "one hundred thirteen trillion, one hundred five billion, ten million, two hundred twenty-three thousand, forty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •