Base | Representation |
---|---|
bin | 11001101101111110111011… |
… | …000100010100010011100100 |
3 | 112211111022112012020011121000 |
4 | 121231332323010110103210 |
5 | 104311203014131230200 |
6 | 1040322304545153300 |
7 | 32553002362140264 |
oct | 3155767304242344 |
9 | 484438465204530 |
10 | 113111102211300 |
11 | 3304a170441706 |
12 | 1082983332b830 |
13 | 4b1643c77459b |
14 | 1dd086c5737a4 |
15 | d1242cbc0300 |
hex | 66dfbb1144e4 |
113111102211300 has 144 divisors (see below), whose sum is σ = 372087788121280. Its totient is φ = 29461496359680.
The previous prime is 113111102211281. The next prime is 113111102211323. The reversal of 113111102211300 is 3112201111311.
113111102211300 is a `hidden beast` number, since 1 + 1 + 31 + 1 + 110 + 221 + 1 + 300 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 487011817 + ... + 487244016.
Almost surely, 2113111102211300 is an apocalyptic number.
113111102211300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113111102211300 is an abundant number, since it is smaller than the sum of its proper divisors (258976685909980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113111102211300 is a wasteful number, since it uses less digits than its factorization.
113111102211300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 974255899 (or 974255886 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 18.
Adding to 113111102211300 its reverse (3112201111311), we get a palindrome (116223303322611).
The spelling of 113111102211300 in words is "one hundred thirteen trillion, one hundred eleven billion, one hundred two million, two hundred eleven thousand, three hundred".
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