Base | Representation |
---|---|
bin | 10101000100011001… |
… | …00010011000000000 |
3 | 1002012021212221111220 |
4 | 22202030202120000 |
5 | 141131122130422 |
6 | 5110220435040 |
7 | 550205006502 |
oct | 124214423000 |
9 | 32167787456 |
10 | 11311130112 |
11 | 4884924517 |
12 | 22380a8a80 |
13 | 10b35214c9 |
14 | 79433dd72 |
15 | 46304ae5c |
hex | 2a2322600 |
11311130112 has 40 divisors (see below), whose sum is σ = 30133561656. Its totient is φ = 3770376192.
The previous prime is 11311130099. The next prime is 11311130113. The reversal of 11311130112 is 21103111311.
It is a junction number, because it is equal to n+sod(n) for n = 11311130091 and 11311130100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11311130113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3680473 + ... + 3683544.
Almost surely, 211311130112 is an apocalyptic number.
11311130112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11311130112 is an abundant number, since it is smaller than the sum of its proper divisors (18822431544).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11311130112 is an frugal number, since it uses more digits than its factorization.
11311130112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7364038 (or 7364022 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 15.
Adding to 11311130112 its reverse (21103111311), we get a palindrome (32414241423).
The spelling of 11311130112 in words is "eleven billion, three hundred eleven million, one hundred thirty thousand, one hundred twelve".
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