1131131300320 has 48 divisors (see below), whose sum is σ = 3054054513888. Its totient is φ = 387816445440.

The previous prime is 1131131300309. The next prime is 1131131300323. The reversal of 1131131300320 is 230031311311.

It is a super-2 number, since 2×1131131300320² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131131300323) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 504968211 + ... + 504970450.

It is an arithmetic number, because the mean of its divisors is an integer number (63626135706).

Almost surely, 2^{1131131300320} is an apocalyptic number.

1131131300320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1131131300320 is an abundant number, since it is smaller than the sum of its proper divisors (1922923213568).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1131131300320 is a wasteful number, since it uses less digits than its factorization.

1131131300320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1009938683 (or 1009938675 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1131131300320 its reverse (230031311311), we get a palindrome (1361162611631).

The spelling of 1131131300320 in words is "one trillion, one hundred thirty-one billion, one hundred thirty-one million, three hundred thousand, three hundred twenty".