Base | Representation |
---|---|
bin | 11001101110010000100011… |
… | …010000100100100001011100 |
3 | 112211120010101022102201022101 |
4 | 121232100203100210201130 |
5 | 104312010300202414400 |
6 | 1040335115100054444 |
7 | 32554242415551514 |
oct | 3156204320444134 |
9 | 484503338381271 |
10 | 113130030123100 |
11 | 330571a378aa21 |
12 | 10831436234424 |
13 | 4b18167cc1bb3 |
14 | 1dd1746304844 |
15 | d12b8976a56a |
hex | 66e42342485c |
113130030123100 has 144 divisors (see below), whose sum is σ = 261547558759872. Its totient is φ = 42326052106240.
The previous prime is 113130030123073. The next prime is 113130030123109. The reversal of 113130030123100 is 1321030031311.
It is a super-2 number, since 2×1131300301231002 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113130030123109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 296865882 + ... + 297246718.
It is an arithmetic number, because the mean of its divisors is an integer number (1816302491388).
Almost surely, 2113130030123100 is an apocalyptic number.
113130030123100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 113130030123100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (130773779379936).
113130030123100 is an abundant number, since it is smaller than the sum of its proper divisors (148417528636772).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113130030123100 is a wasteful number, since it uses less digits than its factorization.
113130030123100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 381952 (or 381945 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 113130030123100 its reverse (1321030031311), we get a palindrome (114451060154411).
The spelling of 113130030123100 in words is "one hundred thirteen trillion, one hundred thirty billion, thirty million, one hundred twenty-three thousand, one hundred".
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