Base | Representation |
---|---|
bin | 11001101110010000110100… |
… | …100110010011100001010100 |
3 | 112211120011010120211111002020 |
4 | 121232100310212103201110 |
5 | 104312011344141031200 |
6 | 1040335204011213140 |
7 | 32554252550342304 |
oct | 3156206446234124 |
9 | 484504116744066 |
10 | 113130321033300 |
11 | 33057332a1607a |
12 | 108314b77471b0 |
13 | 4b181b33594cc |
14 | 1dd1772bcd604 |
15 | d12ba5080ea0 |
hex | 66e434993854 |
113130321033300 has 72 divisors (see below), whose sum is σ = 327324799205376. Its totient is φ = 30167986959360.
The previous prime is 113130321033287. The next prime is 113130321033403. The reversal of 113130321033300 is 3330123031311.
It is a super-3 number, since 3×1131303210333003 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 168077229 + ... + 168748971.
Almost surely, 2113130321033300 is an apocalyptic number.
113130321033300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113130321033300 is an abundant number, since it is smaller than the sum of its proper divisors (214194478172076).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113130321033300 is a wasteful number, since it uses less digits than its factorization.
113130321033300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1233137 (or 1233130 counting only the distinct ones).
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 113130321033300 its reverse (3330123031311), we get a palindrome (116460444064611).
The spelling of 113130321033300 in words is "one hundred thirteen trillion, one hundred thirty billion, three hundred twenty-one million, thirty-three thousand, three hundred".
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