Base | Representation |
---|---|
bin | 1010010010100000100101… |
… | …0100011111001101001110 |
3 | 1111001112002101222000001110 |
4 | 2210220021110133031032 |
5 | 2440323212124121220 |
6 | 40021055543552450 |
7 | 2245226112155604 |
oct | 244501124371516 |
9 | 44045071860043 |
10 | 11313100223310 |
11 | 367194a164946 |
12 | 132867a45b726 |
13 | 640a89315992 |
14 | 2b17b2491874 |
15 | 14942deb5be0 |
hex | a4a0951f34e |
11313100223310 has 64 divisors (see below), whose sum is σ = 27192674995200. Its totient is φ = 3012248155392.
The previous prime is 11313100223267. The next prime is 11313100223323. The reversal of 11313100223310 is 1332200131311.
It is a happy number.
It is a super-2 number, since 2×113131002233102 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 60508551 + ... + 60695229.
It is an arithmetic number, because the mean of its divisors is an integer number (424885546800).
Almost surely, 211313100223310 is an apocalyptic number.
11313100223310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11313100223310 is an abundant number, since it is smaller than the sum of its proper divisors (15879574771890).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313100223310 is a wasteful number, since it uses less digits than its factorization.
11313100223310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 189745.
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 11313100223310 its reverse (1332200131311), we get a palindrome (12645300354621).
The spelling of 11313100223310 in words is "eleven trillion, three hundred thirteen billion, one hundred million, two hundred twenty-three thousand, three hundred ten".
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