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113132025133200 = 24325231425562537
BaseRepresentation
bin11001101110010010011010…
…001010111011100010010000
3112211120022112100101201200100
4121232102122022323202100
5104312023341413230300
61040340045044052400
732554343022061503
oct3156223212734220
9484508470351610
10113132025133200
11330580279295a7
12108318b2394100
134b183c540cc48
141dd189526113a
15d12c54994700
hex66e49a2bb890

113132025133200 has 90 divisors (see below), whose sum is σ = 392599552787234. Its totient is φ = 30168540034560.

The previous prime is 113132025133199. The next prime is 113132025133201. The reversal of 113132025133200 is 2331520231311.

113132025133200 is a `hidden beast` number, since 1 + 1 + 3 + 1 + 320 + 2 + 5 + 1 + 332 + 0 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (113132025133199) and next prime (113132025133201).

It can be written as a sum of positive squares in 3 ways, for example, as 7134540155136 + 105997484978064 = 2671056^2 + 10295508^2 .

It is a tau number, because it is divible by the number of its divisors (90).

It is a super-2 number, since 2×1131320251332002 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (113132025133201) by changing a digit.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 15712777669 + ... + 15712784868.

Almost surely, 2113132025133200 is an apocalyptic number.

113132025133200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

113132025133200 is an abundant number, since it is smaller than the sum of its proper divisors (279467527654034).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113132025133200 is a wasteful number, since it uses less digits than its factorization.

113132025133200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31425562561 (or 31425562547 counting only the distinct ones).

The product of its (nonzero) digits is 3240, while the sum is 27.

Adding to 113132025133200 its reverse (2331520231311), we get a palindrome (115463545364511).

The spelling of 113132025133200 in words is "one hundred thirteen trillion, one hundred thirty-two billion, twenty-five million, one hundred thirty-three thousand, two hundred".

Divisors: 1 2 3 4 5 6 8 9 10 12 15 16 18 20 24 25 30 36 40 45 48 50 60 72 75 80 90 100 120 144 150 180 200 225 240 300 360 400 450 600 720 900 1200 1800 3600 31425562537 62851125074 94276687611 125702250148 157127812685 188553375222 251404500296 282830062833 314255625370 377106750444 471383438055 502809000592 565660125666 628511250740 754213500888 785639063425 942766876110 1131320251332 1257022501480 1414150314165 1508427001776 1571278126850 1885533752220 2262640502664 2356917190275 2514045002960 2828300628330 3142556253700 3771067504440 4525281005328 4713834380550 5656601256660 6285112507400 7070751570825 7542135008880 9427668761100 11313202513320 12570225014800 14141503141650 18855337522200 22626405026640 28283006283300 37710675044400 56566012566600 113132025133200