Base | Representation |
---|---|
bin | 1010010010100000111111… |
… | …1011110101111100000010 |
3 | 1111001112101010210101000120 |
4 | 2210220033323311330002 |
5 | 2440323424032001310 |
6 | 40021114550401110 |
7 | 2245231630401531 |
oct | 244501773657402 |
9 | 44045333711016 |
10 | 11313211203330 |
11 | 36719a6875873 |
12 | 13286ab660196 |
13 | 640aa630212a |
14 | 2b17c3100318 |
15 | 149438ad8b70 |
hex | a4a0fef5f02 |
11313211203330 has 64 divisors (see below), whose sum is σ = 27206250886656. Its totient is φ = 3010801952000.
The previous prime is 11313211203317. The next prime is 11313211203341. The reversal of 11313211203330 is 3330211231311.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 11313211203330.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 29763175 + ... + 30140885.
It is an arithmetic number, because the mean of its divisors is an integer number (425097670104).
Almost surely, 211313211203330 is an apocalyptic number.
11313211203330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11313211203330 is an abundant number, since it is smaller than the sum of its proper divisors (15893039683326).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313211203330 is a wasteful number, since it uses less digits than its factorization.
11313211203330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 379723.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 11313211203330 its reverse (3330211231311), we get a palindrome (14643422434641).
The spelling of 11313211203330 in words is "eleven trillion, three hundred thirteen billion, two hundred eleven million, two hundred three thousand, three hundred thirty".
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