Base | Representation |
---|---|
bin | 10101000100101001… |
… | …11011110001111000 |
3 | 1002012110000210000010 |
4 | 22202110323301320 |
5 | 141132203100240 |
6 | 5110335541520 |
7 | 550232505144 |
oct | 124224736170 |
9 | 32173023003 |
10 | 11313331320 |
11 | 48860982a5 |
12 | 223898a8a0 |
13 | 10b3b123b5 |
14 | 794754224 |
15 | 463333280 |
hex | 2a253bc78 |
11313331320 has 64 divisors (see below), whose sum is σ = 33999023520. Its totient is φ = 3011641344.
The previous prime is 11313331313. The next prime is 11313331327. The reversal of 11313331320 is 2313331311.
11313331320 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (11313331313) and next prime (11313331327).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11313331327) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12457 + ... + 150936.
Almost surely, 211313331320 is an apocalyptic number.
11313331320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11313331320 is an abundant number, since it is smaller than the sum of its proper divisors (22685692200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313331320 is a wasteful number, since it uses less digits than its factorization.
11313331320 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 163984 (or 163980 counting only the distinct ones).
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 11313331320 its reverse (2313331311), we get a palindrome (13626662631).
Subtracting from 11313331320 its reverse (2313331311), we obtain a palindrome (9000000009).
It can be divided in two parts, 113133 and 31320, that added together give a triangular number (144453 = T537).
The spelling of 11313331320 in words is "eleven billion, three hundred thirteen million, three hundred thirty-one thousand, three hundred twenty".
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