Base | Representation |
---|---|
bin | 10000011101101110100… |
… | …110111111001111001100 |
3 | 11000011102110010112221210 |
4 | 100131232212333033030 |
5 | 122014133110104400 |
6 | 2223434524454420 |
7 | 144512641165152 |
oct | 20355646771714 |
9 | 4004373115853 |
10 | 1131432113100 |
11 | 3a6923a27873 |
12 | 1633423aa410 |
13 | 82902a83873 |
14 | 3ca93bc33d2 |
15 | 1e6701b4950 |
hex | 1076e9bf3cc |
1131432113100 has 144 divisors (see below), whose sum is σ = 3470541648896. Its totient is φ = 284090976000.
The previous prime is 1131432113093. The next prime is 1131432113183. The reversal of 1131432113100 is 13112341311.
It is a super-2 number, since 2×11314321131002 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1299946 + ... + 1988145.
Almost surely, 21131432113100 is an apocalyptic number.
1131432113100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1131432113100 is an abundant number, since it is smaller than the sum of its proper divisors (2339109535796).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1131432113100 is a wasteful number, since it uses less digits than its factorization.
1131432113100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3288176 (or 3288169 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 1131432113100 its reverse (13112341311), we get a palindrome (1144544454411).
The spelling of 1131432113100 in words is "one trillion, one hundred thirty-one billion, four hundred thirty-two million, one hundred thirteen thousand, one hundred".
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