Base | Representation |
---|---|
bin | 11001101111101101110010… |
… | …011101010110101010110100 |
3 | 112211220200210100201000001020 |
4 | 121233231302131112222310 |
5 | 104320130313114401400 |
6 | 1040453113141101140 |
7 | 32564415334162254 |
oct | 3157556235265264 |
9 | 484820710630036 |
10 | 113230143122100 |
11 | 330956a7985924 |
12 | 108489159b77b0 |
13 | 4b24731046a44 |
14 | 1dd652237b964 |
15 | d155988762a0 |
hex | 66fb72756ab4 |
113230143122100 has 72 divisors (see below), whose sum is σ = 327735758673120. Its totient is φ = 30183348958080.
The previous prime is 113230143122053. The next prime is 113230143122153. The reversal of 113230143122100 is 1221341032311.
It is a super-2 number, since 2×1132301431221002 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 70175187 + ... + 71770586.
Almost surely, 2113230143122100 is an apocalyptic number.
113230143122100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113230143122100 is an abundant number, since it is smaller than the sum of its proper divisors (214505615551020).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113230143122100 is a wasteful number, since it uses less digits than its factorization.
113230143122100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 141948449 (or 141948442 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 113230143122100 its reverse (1221341032311), we get a palindrome (114451484154411).
The spelling of 113230143122100 in words is "one hundred thirteen trillion, two hundred thirty billion, one hundred forty-three million, one hundred twenty-two thousand, one hundred".
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