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11330002410 = 2351722215691
BaseRepresentation
bin10101000110101001…
…00001110111101010
31002020121101202102220
422203110201313222
5141200440034120
65112133134510
7550524300666
oct124324416752
932217352386
1011330002410
114894544561
12224248a436
1310b73cb54c
14796a538a6
15464a27b40
hex2a3521dea

11330002410 has 32 divisors (see below), whose sum is σ = 28791536832. Its totient is φ = 2843608320.

The previous prime is 11330002381. The next prime is 11330002441. The reversal of 11330002410 is 1420003311.

11330002410 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×113300024102 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 11330002410.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11107336 + ... + 11108355.

It is an arithmetic number, because the mean of its divisors is an integer number (899735526).

Almost surely, 211330002410 is an apocalyptic number.

11330002410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11330002410 is an abundant number, since it is smaller than the sum of its proper divisors (17461534422).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11330002410 is a wasteful number, since it uses less digits than its factorization.

11330002410 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22215718.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 11330002410 its reverse (1420003311), we get a palindrome (12750005721).

Subtracting from 11330002410 its reverse (1420003311), we obtain a palindrome (9909999099).

The spelling of 11330002410 in words is "eleven billion, three hundred thirty million, two thousand, four hundred ten".

Divisors: 1 2 3 5 6 10 15 17 30 34 51 85 102 170 255 510 22215691 44431382 66647073 111078455 133294146 222156910 333235365 377666747 666470730 755333494 1133000241 1888333735 2266000482 3776667470 5665001205 11330002410