11331121201333 has 4 divisors (see below), whose sum is σ = 11332807637760. Its totient is φ = 11329434764908.

The previous prime is 11331121201327. The next prime is 11331121201357. The reversal of 11331121201333 is 33310212113311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11331121201333 - 2⁹ = 11331121200821 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11331121201298 and 11331121201307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11331121201373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 843208135 + ... + 843221572.

It is an arithmetic number, because the mean of its divisors is an integer number (2833201909440).

Almost surely, 2^{11331121201333} is an apocalyptic number.

It is an amenable number.

11331121201333 is a deficient number, since it is larger than the sum of its proper divisors (1686436427).

11331121201333 is an equidigital number, since it uses as much as digits as its factorization.

11331121201333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1686436426.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11331121201333 its reverse (33310212113311), we get a palindrome (44641333314644).

The spelling of 11331121201333 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-one million, two hundred one thousand, three hundred thirty-three".