Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0010100001001100000000 |
3 | 1111010020122000002101020110 |
4 | 2210320330002201030000 |
5 | 2441122124020120112 |
6 | 40033241050311320 |
7 | 2246434663335225 |
oct | 244707402411400 |
9 | 44106560071213 |
10 | 11331131020032 |
11 | 367956207133a |
12 | 1330070a28540 |
13 | 6426a0a39a75 |
14 | 2b260301794c |
15 | 149b36e0413c |
hex | a4e3c0a1300 |
11331131020032 has 36 divisors (see below), whose sum is σ = 30157333081400. Its totient is φ = 3777043673088.
The previous prime is 11331131020003. The next prime is 11331131020043. The reversal of 11331131020032 is 23002013113311.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 11331131019990 and 11331131020008.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7377037657 + ... + 7377039192.
Almost surely, 211331131020032 is an apocalyptic number.
11331131020032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11331131020032 is an abundant number, since it is smaller than the sum of its proper divisors (18826202061368).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11331131020032 is an equidigital number, since it uses as much as digits as its factorization.
11331131020032 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14754076868 (or 14754076854 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 11331131020032 its reverse (23002013113311), we get a palindrome (34333144133343).
The spelling of 11331131020032 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, twenty thousand, thirty-two".
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