Base | Representation |
---|---|
bin | 110100110001000010… |
… | …0001001011010111111 |
3 | 101211111002001010221221 |
4 | 1221202010021122333 |
5 | 3324031441412111 |
6 | 124020024534211 |
7 | 11121015353653 |
oct | 1514204113277 |
9 | 354432033857 |
10 | 113314404031 |
11 | 440690329a4 |
12 | 19b64921367 |
13 | a8bb08351a |
14 | 56ad46ca63 |
15 | 2e33093371 |
hex | 1a621096bf |
113314404031 has 2 divisors, whose sum is σ = 113314404032. Its totient is φ = 113314404030.
The previous prime is 113314404029. The next prime is 113314404079. The reversal of 113314404031 is 130404413311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113314404031 - 21 = 113314404029 is a prime.
It is a super-2 number, since 2×1133144040312 (a number of 23 digits) contains 22 as substring.
Together with 113314404029, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 113314403987 and 113314404005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113314404431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56657202015 + 56657202016.
It is an arithmetic number, because the mean of its divisors is an integer number (56657202016).
Almost surely, 2113314404031 is an apocalyptic number.
113314404031 is a deficient number, since it is larger than the sum of its proper divisors (1).
113314404031 is an equidigital number, since it uses as much as digits as its factorization.
113314404031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 113314404031 its reverse (130404413311), we get a palindrome (243718817342).
The spelling of 113314404031 in words is "one hundred thirteen billion, three hundred fourteen million, four hundred four thousand, thirty-one".
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