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113360652050 = 25217133365473
BaseRepresentation
bin110100110010011010…
…0100100011100010010
3101211121022001210022112
41221210310210130102
53324130311331200
6124024400105322
711122116433562
oct1514464443422
9354538053275
10113360652050
11440921507a8
1219b78305242
13a8c7826c09
1456b566ada2
152e3717b535
hex1a64d24712

113360652050 has 24 divisors (see below), whose sum is σ = 223253803476. Its totient is φ = 42676951040.

The previous prime is 113360652011. The next prime is 113360652079. The reversal of 113360652050 is 50256063311.

It can be written as a sum of positive squares in 6 ways, for example, as 49292436361 + 64068215689 = 222019^2 + 253117^2 .

It is a super-3 number, since 3×1133606520503 (a number of 34 digits) contains 333 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 113360651998 and 113360652016.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 66681887 + ... + 66683586.

Almost surely, 2113360652050 is an apocalyptic number.

113360652050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

113360652050 is a deficient number, since it is larger than the sum of its proper divisors (109893151426).

113360652050 is a wasteful number, since it uses less digits than its factorization.

113360652050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 133365502 (or 133365497 counting only the distinct ones).

The product of its (nonzero) digits is 16200, while the sum is 32.

The spelling of 113360652050 in words is "one hundred thirteen billion, three hundred sixty million, six hundred fifty-two thousand, fifty".

Divisors: 1 2 5 10 17 25 34 50 85 170 425 850 133365473 266730946 666827365 1333654730 2267213041 3334136825 4534426082 6668273650 11336065205 22672130410 56680326025 113360652050