Base | Representation |
---|---|
bin | 10000100001100100010… |
… | …000110101111101111100 |
3 | 11000120001200020212011212 |
4 | 100201210100311331330 |
5 | 122101103144044400 |
6 | 2225355512303552 |
7 | 145020034342352 |
oct | 20414420657574 |
9 | 4016050225155 |
10 | 1135553503100 |
11 | 3a8649392105 |
12 | 1640b26a1bb8 |
13 | 8310b897a83 |
14 | 3cd652d57d2 |
15 | 1e811e17335 |
hex | 10864435f7c |
1135553503100 has 18 divisors (see below), whose sum is σ = 2464151101944. Its totient is φ = 454221401200.
The previous prime is 1135553503061. The next prime is 1135553503163. The reversal of 1135553503100 is 13053555311.
It is a happy number.
It is a super-2 number, since 2×11355535031002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 5677767416 + ... + 5677767615.
Almost surely, 21135553503100 is an apocalyptic number.
1135553503100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1135553503100 is an abundant number, since it is smaller than the sum of its proper divisors (1328597598844).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1135553503100 is a wasteful number, since it uses less digits than its factorization.
1135553503100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11355535045 (or 11355535038 counting only the distinct ones).
The product of its (nonzero) digits is 16875, while the sum is 32.
The spelling of 1135553503100 in words is "one trillion, one hundred thirty-five billion, five hundred fifty-three million, five hundred three thousand, one hundred".
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