Base | Representation |
---|---|
bin | 11001111010111010110100… |
… | …001000010101001010000000 |
3 | 112221122022001002010121120021 |
4 | 121322322310020111022000 |
5 | 104420234042234144440 |
6 | 1042242521450023224 |
7 | 33004142236131511 |
oct | 3172726410251200 |
9 | 487568032117507 |
10 | 114000044053120 |
11 | 333621689905a5 |
12 | 10951b80117b14 |
13 | 4b7c209252514 |
14 | 20218bb06aa08 |
15 | d2a6094c084a |
hex | 67aeb4215280 |
114000044053120 has 128 divisors (see below), whose sum is σ = 273031910749440. Its totient is φ = 45516314578944.
The previous prime is 114000044053097. The next prime is 114000044053283. The reversal of 114000044053120 is 21350440000411.
It is a tau number, because it is divible by the number of its divisors (128).
It is a super-2 number, since 2×1140000440531202 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1209463914 + ... + 1209558166.
It is an arithmetic number, because the mean of its divisors is an integer number (2133061802730).
Almost surely, 2114000044053120 is an apocalyptic number.
114000044053120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 114000044053120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (136515955374720).
114000044053120 is an abundant number, since it is smaller than the sum of its proper divisors (159031866696320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114000044053120 is an equidigital number, since it uses as much as digits as its factorization.
114000044053120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 97722 (or 97710 counting only the distinct ones).
The product of its (nonzero) digits is 1920, while the sum is 25.
Adding to 114000044053120 its reverse (21350440000411), we get a palindrome (135350484053531).
The spelling of 114000044053120 in words is "one hundred fourteen trillion, forty-four million, fifty-three thousand, one hundred twenty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •