Base | Representation |
---|---|
bin | 11001111011010111001100… |
… | …101110000000000100110100 |
3 | 112221202012201002112211121012 |
4 | 121323113030232000010310 |
5 | 104421234001431240000 |
6 | 1042304522012211352 |
7 | 33006301422656654 |
oct | 3173271456000464 |
9 | 487665632484535 |
10 | 114030521352500 |
11 | 33374088596725 |
12 | 10957a66a69b58 |
13 | 4b82055481c8c |
14 | 202316ca3c364 |
15 | d2b2dee7b735 |
hex | 67b5ccb80134 |
114030521352500 has 60 divisors (see below), whose sum is σ = 256101456303924. Its totient is φ = 44379446112000.
The previous prime is 114030521352497. The next prime is 114030521352533. The reversal of 114030521352500 is 5253125030411.
It can be written as a sum of positive squares in 10 ways, for example, as 97145703487504 + 16884817864996 = 9856252^2 + 4109114^2 .
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 616288697 + ... + 616473696.
Almost surely, 2114030521352500 is an apocalyptic number.
114030521352500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
114030521352500 is an abundant number, since it is smaller than the sum of its proper divisors (142070934951424).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114030521352500 is a wasteful number, since it uses less digits than its factorization.
114030521352500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1232762454 (or 1232762437 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 114030521352500 its reverse (5253125030411), we get a palindrome (119283646382911).
The spelling of 114030521352500 in words is "one hundred fourteen trillion, thirty billion, five hundred twenty-one million, three hundred fifty-two thousand, five hundred".
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