Base | Representation |
---|---|
bin | 1010011000010001111010… |
… | …1110001010110110001000 |
3 | 1111101222222212120120011010 |
4 | 2212010132232022312020 |
5 | 2443434233320300000 |
6 | 40134413505003520 |
7 | 2255336014264443 |
oct | 246043656126610 |
9 | 44358885516133 |
10 | 11412243525000 |
11 | 36aa9a5a5390a |
12 | 13439293235a0 |
13 | 64a2294b0336 |
14 | 2b64d982865a |
15 | 14bcd2dc8d50 |
hex | a611eb8ad88 |
11412243525000 has 96 divisors (see below), whose sum is σ = 35660978801280. Its totient is φ = 3043264920000.
The previous prime is 11412243524977. The next prime is 11412243525013. The reversal of 11412243525000 is 52534221411.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 76006624 + ... + 76156623.
It is an arithmetic number, because the mean of its divisors is an integer number (371468529180).
Almost surely, 211412243525000 is an apocalyptic number.
11412243525000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11412243525000 is an abundant number, since it is smaller than the sum of its proper divisors (24248735276280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11412243525000 is an equidigital number, since it uses as much as digits as its factorization.
11412243525000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 152163281 (or 152163257 counting only the distinct ones).
The product of its (nonzero) digits is 9600, while the sum is 30.
Adding to 11412243525000 its reverse (52534221411), we get a palindrome (11464777746411).
The spelling of 11412243525000 in words is "eleven trillion, four hundred twelve billion, two hundred forty-three million, five hundred twenty-five thousand".
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