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1151240472 = 233319926783
BaseRepresentation
bin100010010011110…
…1000100100011000
32222020021002001000
41010213220210120
54324204143342
6310123025000
740346245134
oct10447504430
92866232030
101151240472
11540933008
1228166b160
131546818a5
14acc7a3c4
156b10844c
hex449e8918

1151240472 has 64 divisors (see below), whose sum is σ = 3214080000. Its totient is φ = 381804192.

The previous prime is 1151240471. The next prime is 1151240477. The reversal of 1151240472 is 2740421511.

1151240472 is a `hidden beast` number, since 1 + 151 + 2 + 40 + 472 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1151240471) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29593 + ... + 56375.

It is an arithmetic number, because the mean of its divisors is an integer number (50220000).

Almost surely, 21151240472 is an apocalyptic number.

1151240472 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1151240472, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1607040000).

1151240472 is an abundant number, since it is smaller than the sum of its proper divisors (2062839528).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1151240472 is a wasteful number, since it uses less digits than its factorization.

1151240472 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26997 (or 26987 counting only the distinct ones).

The product of its (nonzero) digits is 2240, while the sum is 27.

The square root of 1151240472 is about 33929.9347479479. The cubic root of 1151240472 is about 1048.0661220250.

Adding to 1151240472 its reverse (2740421511), we get a palindrome (3891661983).

It can be divided in two parts, 11512 and 40472, that added together give a square (51984 = 2282).

The spelling of 1151240472 in words is "one billion, one hundred fifty-one million, two hundred forty thousand, four hundred seventy-two".

Divisors: 1 2 3 4 6 8 9 12 18 24 27 36 54 72 108 199 216 398 597 796 1194 1592 1791 2388 3582 4776 5373 7164 10746 14328 21492 26783 42984 53566 80349 107132 160698 214264 241047 321396 482094 642792 723141 964188 1446282 1928376 2892564 5329817 5785128 10659634 15989451 21319268 31978902 42638536 47968353 63957804 95936706 127915608 143905059 191873412 287810118 383746824 575620236 1151240472