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115213334025244 = 227134760111205443
BaseRepresentation
bin11010001100100100110001…
…110110010001010000011100
3120002221021202100021020222111
4122030210301312101100130
5110100123402002301434
61045012135220523404
733160613551545130
oct3214446166212034
9502837670236874
10115213334025244
113378a7784a7424
1210b09148550564
134c39756008550
1420644d86433c0
15d4be6acda964
hex68c931d9141c

115213334025244 has 96 divisors (see below), whose sum is σ = 253853327702016. Its totient is φ = 44534908684800.

The previous prime is 115213334025211. The next prime is 115213334025247. The reversal of 115213334025244 is 442520433312511.

It is a super-2 number, since 2×1152133340252442 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 115213334025197 and 115213334025206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115213334025247) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4679187 + ... + 15884629.

It is an arithmetic number, because the mean of its divisors is an integer number (2644305496896).

Almost surely, 2115213334025244 is an apocalyptic number.

115213334025244 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 115213334025244, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (126926663851008).

115213334025244 is an abundant number, since it is smaller than the sum of its proper divisors (138639993676772).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

115213334025244 is a wasteful number, since it uses less digits than its factorization.

115213334025244 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11206115 (or 11206113 counting only the distinct ones).

The product of its (nonzero) digits is 345600, while the sum is 40.

Adding to 115213334025244 its reverse (442520433312511), we get a palindrome (557733767337755).

The spelling of 115213334025244 in words is "one hundred fifteen trillion, two hundred thirteen billion, three hundred thirty-four million, twenty-five thousand, two hundred forty-four".

Divisors: 1 2 4 7 13 14 26 28 47 52 91 94 182 188 329 364 601 611 658 1202 1222 1316 2404 2444 4207 4277 7813 8414 8554 15626 16828 17108 28247 31252 54691 56494 109382 112988 197729 218764 367211 395458 734422 790916 1468844 2570477 5140954 10281908 11205443 22410886 44821772 78438101 145670759 156876202 291341518 313752404 526655821 582683036 1019695313 1053311642 2039390626 2106623284 3686590747 4078781252 6734471243 6846525673 7373181494 13468942486 13693051346 14746362988 26937884972 27386102692 47141298701 47925679711 87548126159 94282597402 95851359422 175096252318 188565194804 191702718844 316520148421 350192504636 612836883113 633040296842 1225673766226 1266080593684 2215641038947 2451347532452 4114761929473 4431282077894 8229523858946 8862564155788 16459047717892 28803333506311 57606667012622 115213334025244