Base | Representation |
---|---|
bin | 110101101100000000… |
… | …1110110001101100110 |
3 | 102000121000002021110110 |
4 | 1223120001312031212 |
5 | 3342110114400200 |
6 | 124544244033450 |
7 | 11221036454436 |
oct | 1533001661546 |
9 | 360530067413 |
10 | 115293512550 |
11 | 44994200477 |
12 | 1a417692886 |
13 | ab450c4758 |
14 | 581a24a2c6 |
15 | 2eebbcab50 |
hex | 1ad8076366 |
115293512550 has 24 divisors (see below), whose sum is σ = 285927911496. Its totient is φ = 30744936640.
The previous prime is 115293512513. The next prime is 115293512611. The reversal of 115293512550 is 55215392511.
It is a super-2 number, since 2×1152935125502 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 115293512499 and 115293512508.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 384311559 + ... + 384311858.
It is an arithmetic number, because the mean of its divisors is an integer number (11913662979).
Almost surely, 2115293512550 is an apocalyptic number.
115293512550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
115293512550 is an abundant number, since it is smaller than the sum of its proper divisors (170634398946).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
115293512550 is a wasteful number, since it uses less digits than its factorization.
115293512550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 768623432 (or 768623427 counting only the distinct ones).
The product of its (nonzero) digits is 67500, while the sum is 39.
The spelling of 115293512550 in words is "one hundred fifteen billion, two hundred ninety-three million, five hundred twelve thousand, five hundred fifty".
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