Base | Representation |
---|---|
bin | 11010001101111001101000… |
… | …010111111001101010111100 |
3 | 120010020222220220010001010210 |
4 | 122031321220113321222330 |
5 | 110103121444414440122 |
6 | 1045122044021032420 |
7 | 33200320406243013 |
oct | 3215715027715274 |
9 | 503228826101123 |
10 | 115304443124412 |
11 | 338153811880a3 |
12 | 10b22934855710 |
13 | 4c45215846009 |
14 | 2068a9c96ba7a |
15 | d4e4ee6e940c |
hex | 68de685f9abc |
115304443124412 has 96 divisors (see below), whose sum is σ = 286807667166720. Its totient is φ = 35928568811520.
The previous prime is 115304443124371. The next prime is 115304443124471. The reversal of 115304443124412 is 214421344403511.
It is a super-2 number, since 2×1153044431244122 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 18212164 + ... + 23712692.
It is an arithmetic number, because the mean of its divisors is an integer number (2987579866320).
Almost surely, 2115304443124412 is an apocalyptic number.
115304443124412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 115304443124412, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (143403833583360).
115304443124412 is an abundant number, since it is smaller than the sum of its proper divisors (171503224042308).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
115304443124412 is a wasteful number, since it uses less digits than its factorization.
115304443124412 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5501251 (or 5501249 counting only the distinct ones).
The product of its (nonzero) digits is 184320, while the sum is 39.
Adding to 115304443124412 its reverse (214421344403511), we get a palindrome (329725787527923).
The spelling of 115304443124412 in words is "one hundred fifteen trillion, three hundred four billion, four hundred forty-three million, one hundred twenty-four thousand, four hundred twelve".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •