11532050130 has 32 divisors (see below), whose sum is σ = 29304975744. Its totient is φ = 2894318336.

The previous prime is 11532050099. The next prime is 11532050137. The reversal of 11532050130 is 3105023511.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11532050097 and 11532050106.

It is not an unprimeable number, because it can be changed into a prime (11532050137) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11305422 + ... + 11306441.

It is an arithmetic number, because the mean of its divisors is an integer number (915780492).

Almost surely, 2^11532050130 is an apocalyptic number.

11532050130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11532050130 is an abundant number, since it is smaller than the sum of its proper divisors (17772925614).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11532050130 is a wasteful number, since it uses less digits than its factorization.

11532050130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22611890.

The product of its (nonzero) digits is 450, while the sum is 21.

Adding to 11532050130 its reverse (3105023511), we get a palindrome (14637073641).

The spelling of 11532050130 in words is "eleven billion, five hundred thirty-two million, fifty thousand, one hundred thirty".