Base | Representation |
---|---|
bin | 1010011111101110110011… |
… | …1000100101011010000000 |
3 | 1111212020102022102001222202 |
4 | 2213323230320211122000 |
5 | 3003033421120211222 |
6 | 40313304241252332 |
7 | 2300520212006324 |
oct | 247735470453200 |
9 | 44766368361882 |
10 | 11540256413312 |
11 | 374a216989580 |
12 | 13646b46340a8 |
13 | 65931a7a0c23 |
14 | 2bc7a1031984 |
15 | 1502c6573892 |
hex | a7eece25680 |
11540256413312 has 64 divisors (see below), whose sum is σ = 25614012205440. Its totient is φ = 5133963171840.
The previous prime is 11540256413281. The next prime is 11540256413339. The reversal of 11540256413312 is 21331465204511.
11540256413312 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a tau number, because it is divible by the number of its divisors (64).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 87127493 + ... + 87259844.
It is an arithmetic number, because the mean of its divisors is an integer number (400218940710).
Almost surely, 211540256413312 is an apocalyptic number.
It is an amenable number.
11540256413312 is an abundant number, since it is smaller than the sum of its proper divisors (14073755792128).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11540256413312 is a wasteful number, since it uses less digits than its factorization.
11540256413312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 174387409 (or 174387397 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 38.
The spelling of 11540256413312 in words is "eleven trillion, five hundred forty billion, two hundred fifty-six million, four hundred thirteen thousand, three hundred twelve".
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