1194193141 has 2 divisors, whose sum is σ = 1194193142. Its totient is φ = 1194193140.

The previous prime is 1194193123. The next prime is 1194193159. The reversal of 1194193141 is 1413914911.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (1194193123) and next prime (1194193159).

It can be written as a sum of positive squares in only one way, i.e., 956108241 + 238084900 = 30921^2 + 15430^2 .

It is an emirp because it is prime and its reverse (1413914911) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1194193141 is a prime.

It is a super-2 number, since 2×1194193141² = 2852194516022891762, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1194193097 and 1194193106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1194199141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 597096570 + 597096571.

It is an arithmetic number, because the mean of its divisors is an integer number (597096571).

Almost surely, 2^1194193141 is an apocalyptic number.

It is an amenable number.

1194193141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1194193141 is an equidigital number, since it uses as much as digits as its factorization.

1194193141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3888, while the sum is 34.

The square root of 1194193141 is about 34557.0997191605. The cubic root of 1194193141 is about 1060.9417111894.

The spelling of 1194193141 in words is "one billion, one hundred ninety-four million, one hundred ninety-three thousand, one hundred forty-one".