Base | Representation |
---|---|
bin | 1010111010100000111111… |
… | …0001110001100100001100 |
3 | 1120111020010202000110101020 |
4 | 2232220033301301210030 |
5 | 3033103311223100330 |
6 | 41304524214514140 |
7 | 2346000116200434 |
oct | 256501761614414 |
9 | 46436122013336 |
10 | 12000403331340 |
11 | 3907384915696 |
12 | 1419912965950 |
13 | 690830129598 |
14 | 2d6b733ad2c4 |
15 | 15c258541210 |
hex | aea0fc7190c |
12000403331340 has 72 divisors (see below), whose sum is σ = 35125566289968. Its totient is φ = 3060972435840.
The previous prime is 12000403331303. The next prime is 12000403331387. The reversal of 12000403331340 is 4313330400021.
It is a super-2 number, since 2×120004033313402 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 12000403331340.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 189010531 + ... + 189074010.
Almost surely, 212000403331340 is an apocalyptic number.
12000403331340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12000403331340 is an abundant number, since it is smaller than the sum of its proper divisors (23125162958628).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12000403331340 is a wasteful number, since it uses less digits than its factorization.
12000403331340 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 378084599 (or 378084574 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 12000403331340 its reverse (4313330400021), we get a palindrome (16313733731361).
The spelling of 12000403331340 in words is "twelve trillion, four hundred three million, three hundred thirty-one thousand, three hundred forty".
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