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120005376900 = 223521799672311
BaseRepresentation
bin110111111000011100…
…0001011101110000100
3102110202101021210012220
41233300320023232010
53431232334030100
6131044003412340
711445562605333
oct1576070135604
9373671253186
10120005376900
11469919a7942
121b3116840b0
13b41634a876
145b45d45d1a
1531c56b8aa0
hex1bf0e0bb84

120005376900 has 144 divisors (see below), whose sum is σ = 349667619840. Its totient is φ = 31775990400.

The previous prime is 120005376893. The next prime is 120005376913. The reversal of 120005376900 is 9673500021.

120005376900 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1200053769002 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 51926745 + ... + 51929055.

It is an arithmetic number, because the mean of its divisors is an integer number (2428247360).

Almost surely, 2120005376900 is an apocalyptic number.

120005376900 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120005376900, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (174833809920).

120005376900 is an abundant number, since it is smaller than the sum of its proper divisors (229662242940).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120005376900 is a wasteful number, since it uses less digits than its factorization.

120005376900 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3474 (or 3467 counting only the distinct ones).

The product of its (nonzero) digits is 11340, while the sum is 33.

Adding to 120005376900 its reverse (9673500021), we get a palindrome (129678876921).

The spelling of 120005376900 in words is "one hundred twenty billion, five million, three hundred seventy-six thousand, nine hundred".

Divisors: 1 2 3 4 5 6 10 12 15 20 25 30 50 60 75 100 150 179 300 358 537 716 895 967 1074 1790 1934 2148 2311 2685 2901 3580 3868 4475 4622 4835 5370 5802 6933 8950 9244 9670 10740 11555 11604 13425 13866 14505 17900 19340 23110 24175 26850 27732 29010 34665 46220 48350 53700 57775 58020 69330 72525 96700 115550 138660 145050 173093 173325 231100 290100 346186 346650 413669 519279 692372 693300 827338 865465 1038558 1241007 1654676 1730930 2068345 2077116 2234737 2482014 2596395 3461860 4136690 4327325 4469474 4964028 5192790 6205035 6704211 8273380 8654650 8938948 10341725 10385580 11173685 12410070 12981975 13408422 17309300 20683450 22347370 24820140 25963950 26816844 31025175 33521055 41366900 44694740 51927900 55868425 62050350 67042110 111736850 124100700 134084220 167605275 223473700 335210550 400017923 670421100 800035846 1200053769 1600071692 2000089615 2400107538 4000179230 4800215076 6000268845 8000358460 10000448075 12000537690 20000896150 24001075380 30001344225 40001792300 60002688450 120005376900