Base | Representation |
---|---|
bin | 1010111010100111011000… |
… | …0110011000100110000000 |
3 | 1120111101120101020202221111 |
4 | 2232221312012120212000 |
5 | 3033120320210310422 |
6 | 41305410421133104 |
7 | 2346060502550011 |
oct | 256516606304600 |
9 | 46441511222844 |
10 | 12002120010112 |
11 | 390808593a881 |
12 | 141a11185a194 |
13 | 690a4499563b |
14 | 2d6c97397008 |
15 | 15c3090dba77 |
hex | aea76198980 |
12002120010112 has 32 divisors (see below), whose sum is σ = 25168919434200. Its totient is φ = 5685214740480.
The previous prime is 12002120010109. The next prime is 12002120010161. The reversal of 12002120010112 is 21101002120021.
It is a tau number, because it is divible by the number of its divisors (32).
It is a junction number, because it is equal to n+sod(n) for n = 12002120010092 and 12002120010101.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2467538689 + ... + 2467543552.
Almost surely, 212002120010112 is an apocalyptic number.
It is an amenable number.
12002120010112 is an abundant number, since it is smaller than the sum of its proper divisors (13166799424088).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12002120010112 is an equidigital number, since it uses as much as digits as its factorization.
12002120010112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4935082274 (or 4935082262 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 12002120010112 its reverse (21101002120021), we get a palindrome (33103122130133).
The spelling of 12002120010112 in words is "twelve trillion, two billion, one hundred twenty million, ten thousand, one hundred twelve".
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