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120022000181 is a prime number
BaseRepresentation
bin110111111000111011…
…1100110001000110101
3102110210112120100001222
41233301313212020311
53431301113001211
6131045400000125
711446154111606
oct1576167461065
9373715510058
10120022000181
11469a0321196
121b317160045
13b41991b025
145b48231dad
1531c6d9e1db
hex1bf1de6235

120022000181 has 2 divisors, whose sum is σ = 120022000182. Its totient is φ = 120022000180.

The previous prime is 120022000157. The next prime is 120022000183. The reversal of 120022000181 is 181000220021.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 93718025956 + 26303974225 = 306134^2 + 162185^2 .

It is a cyclic number.

It is not a de Polignac number, because 120022000181 - 214 = 120021983797 is a prime.

It is a super-2 number, since 2×1200220001812 (a number of 23 digits) contains 22 as substring.

Together with 120022000183, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120022000183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60011000090 + 60011000091.

It is an arithmetic number, because the mean of its divisors is an integer number (60011000091).

Almost surely, 2120022000181 is an apocalyptic number.

It is an amenable number.

120022000181 is a deficient number, since it is larger than the sum of its proper divisors (1).

120022000181 is an equidigital number, since it uses as much as digits as its factorization.

120022000181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 17.

The spelling of 120022000181 in words is "one hundred twenty billion, twenty-two million, one hundred eighty-one", and thus it is an aban number.