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1200232110030 = 235616718154083
BaseRepresentation
bin10001011101110011011…
…010001001011111001110
311020202000020110112002020
4101131303122021133032
5124131033410010110
62315213511311010
7152466604414452
oct21356332113716
94222006415066
101200232110030
11423019810868
1217474337b466
1389248705515
144213d2a8662
152134a288d70
hex117736897ce

1200232110030 has 128 divisors (see below), whose sum is σ = 2987949758976. Its totient is φ = 308397196800.

The previous prime is 1200232110019. The next prime is 1200232110043. The reversal of 1200232110030 is 300112320021.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a junction number, because it is equal to n+sod(n) for n = 1200232109991 and 1200232110009.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 22165369 + ... + 22219451.

It is an arithmetic number, because the mean of its divisors is an integer number (23343357492).

Almost surely, 21200232110030 is an apocalyptic number.

1200232110030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 1200232110030, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1493974879488).

1200232110030 is an abundant number, since it is smaller than the sum of its proper divisors (1787717648946).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1200232110030 is a wasteful number, since it uses less digits than its factorization.

1200232110030 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54402.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 1200232110030 its reverse (300112320021), we get a palindrome (1500344430051).

It can be divided in two parts, 12002321 and 10030, that added together give a triangular number (12012351 = T4901).

The spelling of 1200232110030 in words is "one trillion, two hundred billion, two hundred thirty-two million, one hundred ten thousand, thirty".

Divisors: 1 2 3 5 6 10 15 30 61 67 122 134 181 183 201 305 335 362 366 402 543 610 670 905 915 1005 1086 1810 1830 2010 2715 4087 5430 8174 11041 12127 12261 20435 22082 24254 24522 33123 36381 40870 54083 55205 60635 61305 66246 72762 108166 110410 121270 122610 162249 165615 181905 270415 324498 331230 363810 540830 739747 811245 1479494 1622490 2219241 3299063 3623561 3698735 4438482 6598126 7247122 7397470 9789023 9897189 10870683 11096205 16495315 18117805 19578046 19794378 21741366 22192410 29367069 32990630 36235610 48945115 49485945 54353415 58734138 97890230 98971890 108706830 146835345 221037221 293670690 442074442 597130403 655864541 663111663 1105186105 1194260806 1311729082 1326223326 1791391209 1967593623 2210372210 2985652015 3279322705 3315558315 3582782418 3935187246 5971304030 6558645410 6631116630 8956956045 9837968115 17913912090 19675936230 40007737001 80015474002 120023211003 200038685005 240046422006 400077370010 600116055015 1200232110030